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3.2 KiB

"""Filename matching with shell patterns.
fnmatch(FILENAME, PATTERN) matches according to the local convention.
fnmatchcase(FILENAME, PATTERN) always takes case in account.
The functions operate by translating the pattern into a regular
expression. They cache the compiled regular expressions for speed.
The function translate(PATTERN) returns a regular expression
corresponding to PATTERN. (It does not compile it.)
import os
import os.path
import posixpath
import re
#import functools
__all__ = ["filter", "fnmatch", "fnmatchcase", "translate"]
def fnmatch(name, pat):
"""Test whether FILENAME matches PATTERN.
Patterns are Unix shell style:
* matches everything
? matches any single character
[seq] matches any character in seq
[!seq] matches any char not in seq
An initial period in FILENAME is not special.
Both FILENAME and PATTERN are first case-normalized
if the operating system requires it.
If you don't want this, use fnmatchcase(FILENAME, PATTERN).
name = os.path.normcase(name)
pat = os.path.normcase(pat)
return fnmatchcase(name, pat)
#@functools.lru_cache(maxsize=256, typed=True)
def _compile_pattern(pat):
if isinstance(pat, bytes):
pat_str = str(pat, 'ISO-8859-1')
res_str = translate(pat_str)
res = bytes(res_str, 'ISO-8859-1')
res = translate(pat)
return re.compile(res).match
def filter(names, pat):
"""Return the subset of the list NAMES that match PAT."""
result = []
pat = os.path.normcase(pat)
match = _compile_pattern(pat)
if os.path is posixpath:
# normcase on posix is NOP. Optimize it away from the loop.
for name in names:
if match(name):
for name in names:
if match(os.path.normcase(name)):
return result
def fnmatchcase(name, pat):
"""Test whether FILENAME matches PATTERN, including case.
This is a version of fnmatch() which doesn't case-normalize
its arguments.
match = _compile_pattern(pat)
return match(name) is not None
def translate(pat):
"""Translate a shell PATTERN to a regular expression.
There is no way to quote meta-characters.
i, n = 0, len(pat)
res = ''
while i < n:
c = pat[i]
i = i+1
if c == '*':
res = res + '.*'
elif c == '?':
res = res + '.'
elif c == '[':
j = i
if j < n and pat[j] == '!':
j = j+1
if j < n and pat[j] == ']':
j = j+1
while j < n and pat[j] != ']':
j = j+1
if j >= n:
res = res + '\\['
stuff = pat[i:j].replace('\\','\\\\')
i = j+1
if stuff[0] == '!':
stuff = '^' + stuff[1:]
elif stuff[0] == '^':
stuff = '\\' + stuff
res = '%s[%s]' % (res, stuff)
res = res + re.escape(c)
# Original patterns is undefined, see http://bugs.python.org/issue21464
return '(?ms)' + res + '\Z'